A squirrel tosses an acorn with a horizontal velocity of 2+ m/s outward from a tree branch that is 8.0 m above

the ground.How long is the acorn falling through the air?What is the acorn's vertical component of velocity when it reaches the ground?How far(horizontally) from the point on the ground directly under the squirrel does the acorn land?A squirrel tosses an acorn with a horizontal velocity of 2+ m/s outward from a tree branch that is 8.0 m above
I will not give the answer, but will tell you how to solve it:





The time it takes to reach the ground does not depend on the horizontal velocity. The acorn accelerates toward the ground with acceleration g = 9.8m/sec^2. The distance an object with acceleration g travels in time t is





s = .5*g*t^2 (EDIT to change a to g 8/25/06))





Here s = 8m, so you can solve for t. That answers the first part.





The vertical component of velocity is simply vertical acceleration times time. You already have the time, and you know the accleration, so you can figure the vertical velocity.





As long as the acorn is in the air it travels horizontally with the velocity 2m/s. It is in the air for time t, computed above. Now you can compute how far it travels in the horizontal direction before hitting the ground.A squirrel tosses an acorn with a horizontal velocity of 2+ m/s outward from a tree branch that is 8.0 m above
The Answer to Life, the Universe, and Everything is ';42';
thirty- two feet per second, squared. I think, but I haven't been in a Science classroom since 1982.
What, can't finish your own homework?